144v^2-4=0

Solution for 144v^2-4=0 equation:

144v^2-4=0

a = 144; b = 0; c = -4;
Δ = b2-4ac
Δ = 02-4·144·(-4)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*144}=\frac{-48}{288}
=-1/6
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*144}=\frac{48}{288}
=1/6
$